What is the equation of the line that passes through the two points (-2,3) and (2,-3)?

the point-slope form of the equation:    y + 3 = -³/₂(x - 2)    

the slope-intercept form of the equation:   y = -³/₂x

standard form of the equation:        3x + 2y = 0

Step-by-step explanation:

(-2, 3)    ⇒   x₁ = -2,  y₁ = 3

(2, -3)    ⇒   x₂ = 2,  y₂ = -3

So the slope:

The point-slope form of equation is : y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through.

(2, -3)    ⇒   x₀ = 2,  y₀ = -3

Therefore:

y + 3 = -³/₂(x - 2)       ←  the point-slope form of the equation

y + 3 = -³/₂x + 3

y = -³/₂x                    ←  the slope-intercept form of the equation (b=0)

y + ³/₂x = 0

3x + 2y = 0               ←  standard form of the equation

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10