Part A AGES Pedro, Sebastian, and Manuel Martinez are each one year apart in age. The sum of their ages is greater than the age of their father, who is 60. a. Write an inequality to represent this situation, where x is the age of the youngest brother. Multiple choice question. A: x−(x+1)−(x+2)>60 B: x+2x+3x>60 C: x+(x+1)+(x+2)≥60 D:x+(x+1)+(x+2)>60 Part B: Solve the inequality. The older brother is no ( younger/older) than ( 22, 13, 21,12) Based on the solution of the inequality in part b, the youngest brother is no ( younger/older) than ( 19,10,20). The oldest brother is (4,1,2) years older than the youngest brother since each are one year apart.

D: x + (x+1) + (x+2) > 60

Step-by-step explanation:

Let

x = youngest brother age

x + 1 = older brother age

x + 2 = oldest brother age

Fathers age = 60

The inequality is

x + (x+1) + (x+2) > 60

x + x + 1 + x + 2 > 60

3x + 3 > 60

3x > 60 - 3

3x > 57

x > 57/3

x > 19

x + 1

19 + 1

20

x + 2

19 + 2

21

The oldest brother is no younger than 21

The youngest brother is no younger than 19

The oldest brother is 2 years older than the youngest brother since each are one year apart.

answer:   n ≤ -3 or n < -5

step-by-step explanation:

-5 + 2n ≥ -11

+5             +5

2n ≥ -6

2/2 ≤ -6/2

n ≤ -3

-6 - 10n > 44

+6           +6

-10n > 50

-10/-10 50/-10

n < -5

y/x=18

step-by-step explanation: