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If y(x+1)=z, then x=?
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If there is no real number solution to the quadratic equation x^2+2x+c=0 what is a possible value of c? 1 -2 0 3
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Solve this riddle: i am an odd number. i an less than 100. the some of my digit is 12. i am a multiple of 15. what number am i?
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Rewrite so the subject can be y in the formula d=m-y/y+n
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If y(x+1)=z, then x=?...
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