Find the area of the unshaded region for these two problems

1. Area of the right angled ∆ = 1/2 × base × height

height = 16m

base = √20² – 16²

= √400 –256

= √144

= 12 m

Area of the unshaded portion

= 1/2 × base × height

= 1/2 × 12 × 16

= 96m²

2. Area of the rectangle = 300ft × 150ft

= 45000sq. ft

Area of the shaded portion = 100² + (1/2×b×h)

= 10000 + (1/2×120×150)

= 10000 + 9000

= 19000 sq. ft

Area of the unshaded part of the rectangle

= (45000 – 19000)sq. ft

= 26000 sq. ft

europa2433

europa2433

step-by-step explanation:

where is abdul's work? don't see that anywhere posted : /

step-by-step explanation: