Mathematics, 11.01.2021 15:10 anuel504
A pool in the shape of a cylinder with a height of 6 m and a base radius of 7 m is drained for repair. If the rate at which the pool is being drained is 3 m3/min, find the rate at which the water level is falling when the water is 4 m deep to the nearest hundredth.
Answers: 1
), measured in cubic meters, is represented by the following formula:
(1) 
- Radius, measured in meters.
- Height, measured in meters.
(2)
- Rate of change of the volume, measured in cubic meters per minute.
- Rate of change of the radius, measured in meters per minute.
- Rate of change of the height, measured in meters per minute.
(3)
, 
, 
and 
, then the rate of change of the height is:![\dot h = \left(\frac{1}{7\,m} \right)\cdot \left[\frac{-3\,\frac{m^{3}}{min} }{\pi\cdot (7\,m)-2\cdot (4\,m)\cdot \left(0\,\frac{m}{min} \right)} \right]](/tpl/images/1025/9364/19b52.png)
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A pool in the shape of a cylinder with a height of 6 m and a base radius of 7 m is drained for repai...
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