On a coordinate plane, the vertices of a rectangle are (–1, 1), (3, 1), (–1, –4), and (3, –4). What is the perimeter of the rectangle?

Given that,

The vertices of a rectangle are (–1, 1), (3, 1), (–1, –4), and (3, –4).

To find,

The perimeter of the rectangle.

Solution,

Let the points are :

A(–1, 1), B(3, 1), C(3, –4) and D(–1, –4)

Let's find AB and BC using distance formula :

The perimeter of a rectangle = 2(sum of two adjacent sides)

= 2(AB+BC)

= 2(4+5)

= 18 units

So, the perimeter of the rectangle is 18 units.

can you rephrase the question ? it is unclear : -)

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b