The coordinates of the vertices of △XYZ are X(−5, 5), Y(−3, −2), and Z(4, 0). The slope of XZ is __, the slope of YZ is __, and the slope of XY is __. △XYZ __ a right triangle because . -7/2 -5/9 -2/7 2/7 9/5 is is not no two of these slopes have a product of -1 two of these problems have a product of -1

Slope of XZ = -5/9

Slope of YZ  = 2/7

Slope of XY  = -7/2

Step-by-step explanation:

Slope is expressed as;

m = y2-y1/x2-x1

For XZ

X(−5, 5), and Z(4, 0)

Slope of XZ = 0-5/4-(-5)

Slope of XZ = -5/4+5

Slope of XZ = -5/9

For YZ

Y(−3, −2), and Z(4, 0).

Slope of YZ = 0-(-2)/4-(-3)

Slope of YZ = 2/4+3

Slope of YZ  = 2/7

For XY

X(−5, 5), Y(−3, −2)

Slope of XY = -2-5/-3-(-5)

Slope of XY = -7/-3+5

Slope of XY = -7/2

For two lines to be perpendicular, the product of their slope must be -1

Taking the product of XY and YZ

mXY * mYZ = -7/2 * 2/7

mXY * mYZ  = -1

since the product of mXY and mYZ is -1. this shows that line XY is perpendicular to YZ and showing that the triangle XYZ is right triangle

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752