2. At one time, the ratio of in-state to out-of-state tuition at Texas A&M
University in College Station, Texas
was about 3:11. About how much was
the out-of-state tuition if the in-state
tuition at that time was about $2400?

The out-of-state tuition would be $8800.

Step-by-step explanation:

Given that:

The ratio of in-state tuition to out-state tuition = 3:11

If the tuition of in-state is $2400.

Let,

x represent the number of out-of-state tuition.

As the relation is directly proportional.

3 : 11 :: 2400 : x

Product of mean = Product of extreme

11*2400 = 3x

3x = 26400

Dividing both sides by 3

Hence,

The out-of-state tuition would be $8800.

c) the median for town a 30" is greater than the median for town b 25"

step-by-step explanation:

town a, median = q2 = 30

town b, median - q2 = 25

so the median for town a 30" is greater than the median for town b 25"

part a: triangles gcb and epb

part b. sides cg and rp are parallel by definition of parallelogram.

angles cgb and e are congruent by being alternate interior angles of parallel lines cut by a transversal. angles gbc and ebp are congruent because they are vertical angles. by aa similarity, the triangles are similar.

part c. since the triangles are similar, the ratios of the lengths of corresponding sides are equal.

calculation of be:

gb/be = cb/bp

(400 ft)/be = 300/200

(400 ft)/be = 3/2

3be = 2 * 400 ft

3be = 800 ft

be = 800/3 ft

calculation of pe:

gc/pe = cb/bp

(350 ft)/pe = 300/200

(350 ft)/pe = 3/2

3pe = 2 * 350 ft

3pe = 700 ft

pe = 700/3 ft