A submarine travels 6.6 km due West from its base and then turns and travels due South for 3.9 km.
How far away is the submarine from its base?
Give your answer rounded to 1 DP.

km

Step-by-step explanation:

The submarine's path from its base forms a right triangle when its final position is "connected" to the base. We know that the right triangle has legs of km and km, and we need to find the length of its hypotenuse. To do so, we can use the Pythagorean Theorem, which states that in a right triangle, , where and are the lengths of the triangle's legs and is the length of the triangle's hypotenuse. In this case, we know what and are, and we need to solve for c, so after substituting the given values of and into to solve for c, we get:

(Substitute and into the equation)

(Evaluate the squares on the LHS)

(Simplify the LHS)

(Symmetric Property of Equality)

(Take the square root of both sides of the equation)

(Simplify)

is an extraneous solution because you can't have negative distance, if that makes sense, so therefore, the submarine is approximately km away from its base. Hope this helps!

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it is true

step-by-step explanation:

all the combinations add up i used   calculator