You bought 8 bags of dog food and 2 boxes of dog treats for a total of $135. Your friend bought 6 bags of dog food and 4 boxes of dog treats for a total of $110. Each bag of dog food costs the same amount. Each box of dog treats costs the same amount. Write a system of equations, then find the cost of one bag of dog food.

8f + 2t = $135 - - (1)

6f + 4t = $110 - - (2)

$16

Step-by-step explanation:

Given that:

f = dog food

t = dog treat

8f + 2t = $135 - - (1)

6f + 4t = $110 - - (2)

From (1)

4f + t = 67.5

t = 67.5 - 4f

Put t = 67.5 - 4f in (2)

6f + 4(67.5 - 4f)= 110

6f + 270 - 16f = 110

-10f = 110 - 270

-10f = - 160

f = 16

One bag of dog food = $16

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

3030 ur welcome

step-by-step explanation: