Point E on the diagonal of the rectangle ABCD, AE:EC=3:1, and AB:BC=5:4. Find the ratio of DE to BE

3.88 : 3.25   ≈   13 : 11

Step-by-step explanation:

I don't know what are you in, geometry or algebra? I'll post my way of solution. It may need some calculator calculation that I can't give detail of steps here. I just like to explore something, wish it help.

suppose D is the origin, DA = 4 and AB = 5

A (0,4)    B(5,4)    C(5,0)    D(0,0)

AE/AC = 3/4   (i.e. AE/EC = 3/1)

parallel of EF with DC and EG with BC

CF/BC = CE/AC = 1/4

CF = BC x 1/4 = 4 x 1/4 = 1

DG/DC = AE/AC = 3/4  

DG = DC x 1/4 = 5 x 3/4 = 15/4

coordinator of E (3.75 , 1)

length of DE = √3.75² + 1² = 3.88

length of BE = √1.25² + 3² = 3.25

DE : BE = 3.88 : 3.25 ≈ 13: 11     (3.88/13 ≈ 0.29,  3.25/11 ≈ 0.29)

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: