A right triangle has vertices at (0,9), (4,9) and (4, 4). What is the equation of the line that includes the hypotenuse? y =

y = - 1.25x + 9

Step-by-step explanation:

A(0,9)  B(4,9)   C(4,4)

AB² = (4-0)² + (9-9)² = 16

AC² = (4-0)² + (4-9)² = 41

BC² = (4-4)² + (4-9)² = 25

AC is hypotenuse with y interception of 9

slope = 5/4 = -1.25

equation: y = - 1.25x + 9

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

15 units use socratic

step-by-step explanation: 15 units