What is the tenth term of the sequence described by the following f1 = -2, tn =3tn-1

The 10th term will be:

t₁₀ = 39366

Step-by-step explanation:

Given the sequence

tₙ = -3 tₙ₋₁

Given

t₁ = -2

substitute n = 2, to determine the 2nd term

tₙ = -3 tₙ₋₁

t₂ = -3 tₙ₋₁

t₂ = -3 t₂₋₁

t₂ = -3 t₁

t₂ = -3 × -2        ∵ t₁ = -2

t₂ = 6

substitute n = 3, to determine the 3rd term

tₙ = -3 tₙ₋₁

t₃ = -3 t₃₋₁

t₃ = -3 t₂

t₃ = -3 × 6        ∵ t₂ = 6

t₃ = -18

substitute n = 4, to determine the 4th term

tₙ = -3 tₙ₋₁

t₄ = -3 t₄₋₁

t₄ = -3 t₃

t₄ = -3 × -18       ∵ t₃ = -18

t₄ = 54

substitute n = 5, to determine the 5th term

tₙ = -3 tₙ₋₁

t₅ = -3 t₅₋₁

t₅ = -3 t₄

t₅ = -3 × 54      ∵ t₄ = 54

t₅ = -162

substitute n = 6, to determine the 6th term

tₙ = -3 tₙ₋₁

t₆ = -3 t₆₋₁

t₆ = -3 t₅

t₆ = -3 × -162      ∵ t₅ = -162

t₆ = 486

substitute n = 7, to determine the 7th term

tₙ = -3 tₙ₋₁

t₇ = -3 t₇₋₁

t₇ = -3 t₆  

t₇ = -3 × 486      ∵ t₆ = 486

t₇ = -1458

substitute n = 8, to determine the 8th term

tₙ = -3 tₙ₋₁

t₈ = -3 t₈₋₁

t₈ = -3 t₇  

t₈ = -3 ×  -1458      ∵ t₇ = -1458

t₈ = 4374

substitute n = 9, to determine the 9th term

tₙ = -3 tₙ₋₁

t₉ = -3 t₉₋₁

t₉ = -3 t₈  

t₉ = -3 ×  4374      ∵ t₈ = 4374

t₉ = -13122

substitute n = 10, to determine the 10th term

tₙ = -3 tₙ₋₁

t₁₀ = -3 t₁₀₋₁

t₁₀ = -3 t₉  

t₁₀ = -3 × -13122     ∵ t₉ = -13122

t₁₀ = 39366

Therefore, the 10th term will be:

t₁₀ = 39366

plants store their excess carbohydrate in the form of starch so that it could be used as energy source later on. the excess carbohydrate is converted into starch in the plastid i.e. chloroplast & this process occurs in the presence of sunlight. it is an insoluble polymer of glucose which gets stored in cell organelles named as amyloplasts. in some plants, starch is also stored in roots and embryos.