Mathematics, 09.01.2021 08:10 kirbymichellrow6zq9

If you stretch a spring to 5 ft, it has 310 ft-lb of potential energy (PE). Potential energy varies directly as the square of the stretched length (l). The potential energy can be represented by the formula PE=1/2 kl^2, , where k is the spring constant. a. What is the value of the spring constant for this spring?
b. How many ft-lbs of PE would an 8 ft length of spring have?

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If you stretch a spring to 5 ft, it has 310 ft-lb of potential energy (PE). Potential energy varies...