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Step-by-step explanation:

Given functions are,

f(x) = 2x - 3

g(x) = x³ - 2

h(x) = x² - 3x + 5

(10). f(4) = 2(4) - 3

           = 5

    g(-2) = (-2)³ - 2

             = -8 - 2

             = -10

    f(4) + g(-2) = 5 -10 = -5

(11). g(3) = 3³ - 2 = 25

     h(1) = 1² - 3(1) + 5

            = 1 - 3 + 5

            = 3

      g(3) - h(1) = 25 - 3 = 22

(12). f(2) = 2(2) - 2 = 2

      h(-3) = (-3)² - 3(-3) + 5

              = -27 + 9 + 5

              = -13

       f(2).h(-3) = 2(-13) = -26

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: