Write the equation of the line parallel to the line 3x + 5y = 7 and passes through the point (-1, 3) in standard form. Please help

Step-by-step explanation:

3x + 5y = 7         {subtract 3x from both sides}

5y = -3x + 7        {divide both sides by 5}

y = -³/₅x + ⁷/₅        ←  slope-intercept form

y=m₁x+b₁   ║   y=m₂x+b₂   ⇔    m₁ = m₂

{Two lines are parallel if  their slopes are equal}

y = -³/₅x + ⁷/₅     ⇒   m₁ = -³/₅    ⇒    m₂ = -³/₅

(-1, 3)  ⇒  x₁ = -1,  y₁ = 3

The point-slope form:

y - 3 = -³/₅(x - (-1))

y - 3 = -³/₅(x + 1)           {myltiply both sides by 5}

5y - 15 = -3x - 3           {add 3x to both sides}

3x + 5y - 15 = - 3        {add 15 to both sides}

3x + 5y = 12

answer: 414,377,008

step-by-step explanation:

just multiply it