100 points please help its just these two left

350N, 800 N

Step-by-step explanation:

for question no 6

mass (m) = 70 kg

acceleration (a) = 5 m/s²

Force (F) = m * a = 70 * 5 = 350 N

for question no 7

mass (m) = 80 kg

acceleration (a) = 10 m/s²

Force (F) = m * a = 80 * 10 = 800 N

Hope it will help :)❤

350N, 800 N

Step-by-step explanation:

for question no 6

mass (m) = 70 kg

acceleration (a) = 5 m/s²

Force (F) = m * a = 70 * 5 = 350 N

for question no 7

mass (m) = 80 kg

acceleration (a) = 10 m/s²

Force (F) = m * a = 80 * 10 = 800 N

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)