Given \qquad m \angle QPS = 107^\circm∠QPS=107 ∘ m, angle, Q, P, S, equals, 107, degrees \qquad m \angle RPS = 4x + 27^\circm∠RPS=4x+27 ∘ m, angle, R, P, S, equals, 4, x, plus, 27, degrees \qquad m \angle QPR = 9x - 115^\circm∠QPR=9x−115 ∘ m, angle, Q, P, R, equals, 9, x, minus, 115, degrees Find m\angle QPRm∠QPRm, angle, Q, P, R:

20°

Step-by-step explanation:

4x+27°+9x-115°=107°

4x+9x + 27°-115°=107°

13x-88°=107°

add 88 on both sides

13x=195°

divide 13 on both sides

x=15

9(15°)-115°

135°-115° = 20

The answer is 20

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.