The equation of line AB is y = 2x + 4. What is the equation of a line parallel to line AB in slope-intercept form that contains the point (3, −2)? y = 2x − 4
y = one half x − one half
y = negative one half x − seven halves
y = 2x − 8

y = 2x-8

Step-by-step explanation:

If two linear equations are parallel, they have the same slope.

Therefore, y = 2x + b passes through (3,-2)

-2 = 2*3 + b = 6+b

b = -8

is right  y = 2x − 8

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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