How many ways are there to choose five doughnuts if there are eight varieties (and only the type of each doughnut matters)?

There are 56 ways to choose 5 from 8 varieties.

Step-by-step explanation:

a) Choosing 5 out of 8

This is a combination problem, given by the formula below:

C(n,r)=?

C(n,r)=C(8,5)

=8!/(5!(8−5)!)

= 56

b) A combination is the number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter and replacements are not allowed. The result of this combination of 5 out of 8 varieties shows that there 56 ways one can choose.  The formula is given by 8 factorial divided by (5 factorial by 3 factorial).

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204