Billy is playing a game using a bag with 11 marbles inside. The bag contains 3 red, 3 orange, 1 yellow, 2 purple marbles, and 2 Pink. Each time he picks an orange marble, she will win a prize. If he picks a marble twice, WITHOUT replacement, what is the probability he will win a prize on both picks? 5/110 5/21 3/55 9/121

3/55

Step-by-step explanation:

From the information given, the bag contains 3 red, 3 orange, 1 yellow, 2 purple marbles, and 2 Pink marbles. Each time he picks an orange marble, she will win a prize.

If he picks a marble the first time, the probability of picking an orange marble will be 3/11. After that we will have 10 marbles left as one has been picked and have 2 orange marbles left, then the probability of picking another orange marble will be 2/10.

Therefore, the probability he will win a prize on both picks will be:

= 3/11 × 2/10

= 6/110

= 3/55

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

i dont know sorry

step-by-step explanation: