Two cars leave the same parking lot, with one heading north and the other heading east. After several minutes, the eastbound car has traveled 3 kilometers. If the two cars are now a
straight-line distance of 6 kilometers apart, how far has the northbound car traveled? If
necessary, round to the nearest tenth.

wouldn't it be 3 kilometers because 3 this way plus 3 that way = 6 away from each other?

d

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v