The cube in the image has a volume of 1000 cubic feet. the other solid has the same base and height as teh cube, but the length of its slanted sides is 2 units longer than the height. what is the volume of the tilted solid.

The volume of the tilted solid is 1000 ft³.

Step-by-step explanation:

Since, The volume of a cube = ( side )³

⇒ 1000 = (side)³ ⇒ side = 10

Hence, the side of the given cube = 10 feet

Since, the base of a cube = square having side 10 feet.

When we tilted the cube by 2 units,

Then, the base of the new solid = Rhombus having height 10 meters and base 10 feet,

Since, the square and rhombus are lying in the same base ( Shown in diagram)

Area of rhombus (Base of new solid) = Area of square having side 10 feet = 100 ft²

Since, the height of new solid is also 10 feet.

Thus, the volume of new solid = Area of its base × height

=  10 × 100

= 1000 ft²

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3