The corners of a square are cut off two centimeters from each corner to form an octagon. If the octagon is 10 centimeters wide, what is its area? can't be determined

84 cm 2

92 cm 2

100cm 2

asap

Area of octagon = 100 - 2 =  98  cm²

Step-by-step explanation:

Area of octagon = area of square - area of 4 triangles that are formed in four corners

Area of square:

Side = Width of the octagon = 10 cm

Area = side * side

      = 10 * 10

     = 100 cm²

Area of triangle:

Base =  2cm

height =  2 cm

Area =

       =

      = 2  cm²

Area of octagon = 100 - 2 =  98  cm²

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer: 819.89 miles across america

step-by-step explanation: