I am three years younger than my brother and I am two years older than my sister my mom's age is 1 less than three times my brothers age when you add all these ages up you get 87 what are our ages

my age = 13years,My brother's age =16years,My sister's age=11years,my mom's age =47years

Step-by-step explanation:

Step 1

Let my age be represented as x

My brother's age be represented as x+3

My sister's age =x-2

and my mum's age be 3(x+3)-1  with the total of all our ages = 87 Giving us the equation

x+ x+3+ x-2+ 3(x+3)-1 = 87

Step 2 ---Solving

x+ x+3+ x-2+ 3(x+3)-1 = 87

x+ x+3+ x-2+ 3x+9 -1 = 87

6x + 9= 87

6x= 87-9

6x= 78

x =78/6 = 13

Therefore my age = 13years

My brother's age = x+ 3 = 13+3= 16years

My sister's age = x-2 =13-2 = 11years

my mom's age = 3(x+3)-1= 3(13+ 3)- 1= 3 x 16 - 1 = 47years

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.