Find the probability that a number chosen at random from the integers between 5 and 16 inclusive is a multiple of 3 or a mutiple of 2

Numbers between 5 and 16 are:-

6, 7, 8, 9, 10, 11, 12, 13, 14 , 15 and 16.

Therefore, total number of outcomes =11

Numbers inclusive between 5 and 16 which are divisible by 2 or 3 are-

6 , 8, 9 ,10 ,12, 14 and 15.

Number of favourable outcomes = 7

Therefore, probability of getting a number which is either a multiple of 2 or 3 is:

p(e) = \frac{7}{11}p(e)=

11

7

HENCE, THE REQUIRED PROBABILITY IS = 7 / 11.

Step-by-step explanation: does this help?

maybe showing the graph would

step-by-step explanation:

-387129 iq

in mathematics, a constraint is a condition of an optimization problem that the solution must satisfy. there are several types of constraints—primarily equality constraints, inequality constraints, and integer constraints. the set of candidate solutions that satisfy all constraints is called the feasible set.

hoped i'm right lol