17 apples and 12 oranges cost $10.44. 3 apples and 4 oranges cost $2.84. How much does 1 orange cost?

0.48$

Step-by-step explanation:

Cost of 1 Apple = A

Cost of 1 Orange = O

Six apples and three oranges cost $3.36 equivalent to:

6A + 3O = 3.36 (1st equation).

Two apples and five oranges cost $3.04 equivalent to:

2A + 5O = 3.04 (2nd equation).

Now we have to solve the 2 equations with 2 uknowns (the cost of 1 Apple = A, and the cost of 1 Orange = O).

6A + 3O = 3.36 (Equation 1)

2A + 5O = 3.04 (Equation 2), multiplying this equation by 3 we get:

6A + 3O = 3.36 (Equation 1)

6A + 15O = 9.12 (Equation 2), Now equation 2 minus equation 1 we get:

6A-6A +15O -3O = 9.12-3.36 equivalent to:

12O = 5.76 => O = 5.76/12 = 0.48 ( the cost of one Orange is 0.48$)

Go back to equation 1 and solve for the cost of 1 apple:

6A + 3x0.48 = 3.36 =>

6A + 1.44 = 3.36 =>

6A = 1.92 =>

A = 1.92/6 = 0.32 ( the cost of one apple is 0.32$)

Summary: The cost of one apple is 0.32$ and the cost of one orange is 0.48$.

the answer is a

step-by-step explanation:

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.