A house cost $320,000 in 2005. By the year 2019, its value was $560,000. What was the growth rate as a percent for that 14-year period? (Remember, i=(p^2/p^1)^1n−1

Growth rate = 4.08%

Step-by-step explanation:

Rate of interest 'i' for the growth in the cost of the house,

i =

Here 'n' = Duration or time (in years)

i =

i =

i = 1.0408 - 1

i = 0.0408

i = 4.08%

Therefore, growth rate for this period is 4.08%.

answer: i think one of the answer is $150 and $300?

step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92