Which Equation can be used to represent "six added to twice the sum of a number and four is equal to one-half of the difference of three and the number"? 1. 6+2(x+4)=1/2(3-x)
2. 6+2(x+4)=1/2 (x-3)
3. (6+2)(x+4)=1/2(3-x)
4.(6+2)(x+4)÷1/2(x-3)

many reason,

step-by-step explanation:

the awnser is visionary

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x=0.8898305 is the answer to that equation

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .