The chance of rolling
a 3
on a normal, 6 sided die.

wouldn’t it be a 1 out of 6 chances since there is 6 sides on the dice

ANSWER: 1/6

Step-by-step explanation:

A fairly basic and fundamental problem in Probability, but still worth doing as an example of good mathematics.

Assumptions

The number cube is fair, that is not biased in any manner.

Key Points to Note.

Each roll of the number cube is an Independant Event, that is the outcome of any toss has no impact whatsoever on the outcome of any other toss.

The Probability of NOT achieving a specific outcome is equivalent TO ACHIEVING all other outcomes.

The Probability of achieving two sequential outcomes, is the Probability of achieving the first outcome multiplied by the Probability of achieving the second.

Analysis

What is the probability of rolling a 3 on a 6-sided number cube and then NOT rolling a 3 on a 6-sided number cube?

There are 6 sides on the number cube, each with an equal probability of being a specific outcome.

Therefore the Probability of a 3 as the outcome, is ( 1/6 ).

What is the probability of NOT rolling a 3 on a 6-sided number cube?

The Probability of NOT rolling a 3, is the same as either 1 - Probability (3) or Probability (1, 2, 4, 5, 6), which is equivalent to ( 5/6 )

Sequential Probabilities.

What is the probability of rolling a 3 on a 6-sided number cube AND THEN NOT rolling a 3 on a 6-sided number cube?

P( 3 ) then P( Not a 3 ) = ( 1/6 ) * ( 5/6 ) which equals ( 5/36 )

A Further Point to Note

Because the two rolls of the number cube are independant, the final probability is independant of the order of which outcome is first sought.

christopher is 272,195 year old

step-by-step explanation:

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~