Which statement compares the two numbers correctly? six times one tenth plus three times one hundredth plus two times one thousandth six hundred twenty-nine thousandths

six times one tenth plus three times one hundredth plus two times one thousandth six times one tenth plus three times one hundredth plus two times one thousandth

Step-by-step explanation:

So, we have-

(6 x .1) + (3 x .01) + (2  x .001)

So, we will solve inside of the parenthesis first.

6 x .1  = .6

So, we got that settled next-

3 x .01 = .03

We got that settled last-

2 x .001 = .002

Lastly, we add them all.

.6 + .03 + .002 =  .632

Now we compare.

.632 > .629

So, there is your answer!

Hope this helps!

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )