Please help, I don't know how to do this. f(x)=(x+2)(x−4)
1) What are the zeros of the function?
2) What is the vertex of the parabola?

(a) Zeroes of the function is -2,4.

(b) The vertex of the parabola is (1,-9).

Step-by-step explanation:

Given,

f(x)=(x+2)(x−4)

(a)To find the zeros of the function put f(x)=0.

(x+2)(x-4)=0

x+2 = 0        or      x-4 = 0

x = -2,4

Hence, zeroes of the function is -2,4.

(b)Now,

f(x)=(x+2)(x−4)

 .......(i)

We know that,

If is the equation of parabola the (h,k) is the vertex of the parabola.

On comparing with equation (i), we get

h = 1

k = -9

Hence, the vertex of the parabola is (1,-9).

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8