Which polynomial function f(x) has a leading coefficient of 1, roots –4, 2, and 9 with multiplicity 1, and root –5 with multiplicity 3?

f(x) = (x + 5)(x + 5)(x + 5)(x + 4)(x - 2)(x - 9)

Step-by-step explanation:

The polynomial function f(x) possessing a key coefficient of 1:

= 0

By opening the above equation;

f(x) = (x + 5)(x + 5)(x + 5)(x + 4)(x - 2)(x - 9)

∵ Thus, the above polynomial function makes the coefficient 1 with a multiplicity of 3 for root - 5 and 1 for -4, 2, and 9.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

152 thatbk ypi vjsl b abjb uoabr