Construct a ∆ PQR , given that PQ = 5.5 cm ,QR = 4.8 cm and PR = 4.2 cm . Write steps of construction .

Step-by-step explanation:

AT first, draw the reference line, which are given. If I take PQ as base, I won't need to draw PQ line as reference.

I took PQ(5.5cm) as base. Then, take 4.8cm in your compass by centering at point Q. Draw an arc. Then take 4.2 cm in your compass from the reference line which you have drawn and then centre at point P and draw an arc. Both the arcs will meet at one point. Then join the lines to form the Triangle PQR

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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step-by-step explanation: