A rock is thrown straight up from the top of a bridge that is 75 ft high with an initial velocity of 32 ft/s. The height of the object can be modeled by the equation s(t) = -16t^2 + 32t + 75. Determine the time(s) the ball is lower than the bridge in interval notation. In two or more complete sentences, explain why (-∞, 0) is not included in the solution.

I tried to solve it, but given that the Critical Numbers/Roots are 0 and 2, the solution should be (-∞, 0) ∪ (2, ∞)

Step-by-step explanation:

When -16t² + 32t + 75 < 75, -16t² + 32t < 0.

=> 16t(2 - t) < 0, t < 0 or t > 2.

However t < 0 is rejected as time cannot be a negative value. Hence the solution in interval notation is (2, ∞).

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°