PLEASE HELP Question and answer choices are in the screenshot below

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Choice B

Explanation:

Let's say we had segment PQ. So the endpoints are P and Q. Let M be the midpoint of segment PQ.

Furthermore, let P have coordinates (x+6, y/3). Dividing by 3 is the same as multiplying by 1/3. So (1/3)y is the same as y/3.

Let Q have the coordinates (r,s). The goal is to express r and s in terms of x and y, as the answer choices indicate.

The midpoint M is located at (2,-5)

For now, let's focus on the x coordinates of each point

If we average the x coordinates of P and Q, we'll get the x coordinate of M

So we add up (x+6) and r, then divide by 2, and we should get 2 as a result

( (x coord of P) + (x coord of Q) )/2 = x coord of M

( (x+6) + (r) )/2 = 2

(x+6+r)/2 = 2

Let's solve for r

(x+6+r)/2 = 2

x+6+r = 2*2

x+6+r = 4

r = 4-x-6

r = -2-x

The x coordinate of point Q is -2-x

We'll follow the same basic idea for the y coordinates

We then get

( (y coord of P) + (y coord of Q) )/2 = y coord of M

( (y/3) + (s) )/2 = -5

(y/3) + s = -5*2

(y/3) + s = -10

Now solve for s

(y/3) + s = -10

s = -10-(y/3)

This is the y coordinate of point Q.

We found

Point Q is therefore located at (-2-x,  -10-(y/3) )

This points to choice B as the final answer.

answer would be 8.64 or s = 11π/4 inches

step-by-step explanation:

s = r θ  

where s = arc length  

r = radius = 3 inches  

θ = central angle in radians = ( π /180)*165  

s = 3(π/180)*165  

= 8.64 inches

wow ok so the answer is 1k or just k

because of combining like terms xd