How many unique triangles can be formed with two side lengths of 10 centimeters and one 40° angle?

Step-by-step explanation:

Given two sides of 10 cm and one 40° angle

If we use these, we'll get isosceles triangle with:

1. Included 40° angle.

Then the other angles will be same and measure:

2. Adjacent 40° angle. Then one of the angles must be 40° angle as opposite of 10 cm sides.

The remaining angle will measure:

There no more unique triangles possible, so the answer is two.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation: