26 POINTS What is the simplified form of StartFractio negative 24 m Superscript 5 Baseline n Superscript 4 Baseline Over 8 m Superscript negative 7 Baseline n Superscript negative 2 Baseline EndFraction? Assume m not-equals 0, n not-equals 0.
StartFraction 3 Over m Superscript 35 Baseline n Superscript 8 Baseline EndFraction
Negative StartFraction 3 n squared Over m squared EndFraction
Negative 3 m Superscript 12 Baseline n Superscript 6 Baseline
3 m Superscript 35 Baseline n Superscript 8 Baseline

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

this is not the answer this is just a question. is this middle school math?

step-by-step explanation:

2nd one in the first row is correct