What is the equation of the line that passes through the point (-5, -2) and has a
slope of -6/5

Step-by-step explanation:

you are given the slope m = -6/5 and one point (x1,y1) as (-5,-2)

next use  the point-slope formula [y-y1 = m(x-x1) ] and plug in the point and the slope

y-(-2) = -6/5(x-(-2))    ( they are making this tuff with all the minus signs :/ )

y+2 = -6/5(x+2)         ( nice looks better, distribute the -6/5 )

y + 2 = -6/5x -12/5    (move the 2 over )

y = -6/5x - 12/5 -2      ( 2 = 10/5 )

y = -6/5x -12/5 - 10/5    (add the fractions )

y = -6/5x -22/5    

that's in the form of the slope-intercept now  [ y = mx + b ] so you're done :)

1. sometimes

2. never true

3. sometimes

step-by-step explanation:

these are pretty self explanatory if you know what supp right and com angles are