I want help, can you help me..

5. The Answer is 45.

6. 75

7. 110

8. 30

9. 12

10. 4

11. 5

12. 9

13. 60

14. 60

Step-by-step explanation:

When you solve it out, you know that vertical angles are congruent. So the top angle is 42. Then you need to find out the angle adjacent to the 87. This is a supplementary angle. Supplementary angles add up to 180. So, 180 - 87 = x. This comes out to 93. Then you just need to find ?. All angles in a triangle add up to 180. So 180 - 93 -42 = 45. ? = 45

For this one we know that the angles in a triangle add up to 180. So, 180 - 35 - 70 = 75. Vertical angles are congruent so ? is also equal to 75.

For this one, we know supplementary angles add up to 180. We use this for every angle. 180 - 145 = 35. 180 - 105 = 75. Angles in a triangle add up to 180 so, 180 - 75 - 35 = 70. We know the other angle in the triangle, we now need to find the angle that is supplementary. We know they add up to 180 so, 180 - 70 = 110. ? = 110

We know 2 of the angles, 90 and 60. We can solve for the third angle. 180 - 90 - 60 = 30. Vertical angles are congruent so ? also equals 30.

We now 2 angles. 60 and 70. We can find the third angle. 180 - 60 -70 = 50. We now need to solve for x. We can subtract 14 from 50 then divide it by 3. We get 12. X is = 12.

We know 2 angles. 65 and 90. This means the third angle is 25. We need to solve for x so 25 - 1 = 24. Then divide that by 6. We get 4. X = 4.

We know 2 angles. 70 and 70. This means the third angle is 40. We can divide that by 8 to find x. X = 5.

We know 2 angles. 70 and 90. This means the third angle is 20. We can subtract 2 to get 18. Then divide by 2. We get 9. X = 9.

We first need to find the last angle in the first triangle. 180 - 85 - 50. The third angle is 45. We now know 2 angles in the second triangle. We can now solve for ?. 180 - 75 - 45. ? = 60

We first need to find the last angle in the first triangle. 180 - 70 - 70. 40 is the last angle. We now have 180 - 40 - 80. It comes out to 60. ? = 60.

its 69.420

step-by-step explanation: