en un auditorio de un pueblo hubo 600 personas en un evento, en total se recaudaron 13 mil pesos. el precio de admision fue 25 pesos para los adultos y 15 pesos para los niños. plantea un sistema de ecuaciones que represente los sucedido

There were 200 children and 400 adults in the auditorium.

Step-by-step explanation:

Given that there were a total of 600 peoples in the event.

Let there were n children in the event.

So, the number of an adult in the event = 600-n

As the admission price for one child = 15 pesos

and the admission price for one adult = 25 pesos.

So, total admission price = 15n+25(600-n)

As total money raised = 13000 pesos

So, 15n+25(600-n)=13000

15n+15000-25n=13000

10n=15000-13000=2000

n=2000/10=200

Therefore, number of children = 200

and the number of adults = 600-200=400.

Hence, there were 200 children and 400 adults in the auditorium.

number one is the correct answer

step-by-step explanation: dogs and cats are mentioned, no other animals

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3