Solve for x -5|x+ 1| =10

Step-by-step explanation:

x-5(x+1)=10

x-5x-5=10

-4x-5-10=0

-4x-15=0

-4x=-15

x=-15/-4

x=3.75

sorry...the answer is wrong..dont write

no solution

Step-by-step explanation:

Given

- 5 | x + 1 | = 10 ( divide both sides by - 5 )

| x + 1 | = - 2

To have a solution the right side of the equation must be positive or zero

No absolute value can have a negative solution

Thus the equation has no solution

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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