A line with a slope of 5 passes through the point (2, 5). What is its equation in slope-intercept form?

Step-by-step explanation:

slope-intercept form of equation:  y = mx + b

where m is slope and b is y-intercept

If line y=ax+b passes through point (x₀,y₀) that means

that the equation y₀=ax₀+b is true

(2, 5)    ⇒   x=2,   y=5

m = 5

So:

              5 = 5×2 + b

               5 = 10 + b

               b = -5

Therefore equation in  slope-intercept form:

                                                                      y = 5x + (-5)

                                                                      y = 5x - 5                          

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