On average, at least 25,000 pieces of luggage are lost or misdirected
each day by United States airlines. Of
these, 98% are located by the airlines
within 5 days. From a given day’s lost
luggage, at least how many pieces of
luggage are still lost after 5 days?
WRITE AND SOLVE AN INEQUALITY (people just solve without an inequality!)

98% of 25,000 is 24,500.

So from this, we can make the inequality:

25,000 - 500x

x = 5 days.

May I have brainliest please? :)

500

Step-by-step explanation:

At least means 25000 and bigger. But 25000 is included in the inequality.

You should write an inequality to to represent the number of pieces of luggage

x ≥ 25000

100% - 98% = 2%

2% of all luggage lost is never found. Multiply both sides of x ≥ 25000 by 2%

2 percent x ≥ 25000 * 2%

2 percent x ≥ 500

Note that 2 percent is not an algebraic variable. 2% is. 2% = 2/100, but that is not what you want on the left.

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9

5

step-by-step explanation: