For the picture of the kite below, how would you prove that triangle BCE is congruent to triangle DCE if ∠1 is congruent to ∠2 and ∠3 is congruent to ∠4? Write a proof plan to answer.

∆ adc is congruent to ∆ abc by asa congruence rule where CA is common side,

so CD and CB are congruent therefore angle cbe is same as angle cde

so ∆ bce and ∆ dce are congruent by ASA congruence rule

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

if the probability is 1/12, 75 people will receive a $25 gift card

step-by-step explanation: