Which statement best describes the area of Triangle ABC shown below? A triangle ABC is shown on a grid. The vertex A is on ordered pair 3 and 5, vertex B is on ordered pair 4 and 1, and the vertex C is on ordered pair 2 and 1.
(1 point)

It is twice the area of a square of side length 2 units.
It is one-half the area of a square of side length 2 units.
It is twice the area of a rectangle of length 2 units and width 4 units.
It is one-half the area of a rectangle of length 2 units and width 4 units.

It is one-half the area of a rectangle of length 4 units and width 5 units.

Step-by-step explanation:

answer is : muchas/tipicas

have a nice day!

~recklesschicken

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)