What is the height of a triangular prism that has a height of 9 meters and a base with the following deminsions 4m 14m

252m^3

Step-by-step explanation:

A solid having a triangular base is what we call a triangular prism. For every prism, its volume is always equal to the area of its base times its height. In other words:

V = AxH

V - volume

A- area

H - height of prism

We know that:

h = 4 m (side of base)

b = 14 (other base side)

A = bh/2 = 14x4/2 = 28 m^2

And then: V = A x H = 28 x 9 = 252 m^3

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation: