The length of a cell phone is 1.4 inches and the width is
4.4 inches. The company making the cell phone wants to make a new version whose length will be
1.75 inches. Assuming the side lengths in the new phone are proportional to the old phone, what will be the width of the new phone?

The width of new phone = 5.5 inches

Step-by-step explanation:

Given that:

Length of cell phone = 1.4 inches

Width of cell phone = 4.4 inches

Ratio of length to width = 1.4 : 4.4

Length of new version = 1.75 inches

Width of new version = x

Ratio of length to width = 1.75 : x

As the relation is proportional;

Product of mean = Product of extreme

4.4 * 1.75 = 1.4x

7.7 = 1.4x

1.4x = 7.7

Dividing both sides by 1.4

Hence,

The width of new phone = 5.5 inches

the answer is 62

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)