What i the solution of the equation?
64 x-3 = 4 x+15

I kind of feel that it's an exponential equation

so remember
if
a^x=a^y, whee a=a then x=y
and
(x^m)^n=x^(mn)

so



64=4^3



3(x-3)=x+15
3x-9=x+15
minus x both sides
2x-9=15
minus 9 both sides
2x=6
divide 2
x=3

if it was just normal thing like 64x-3=4x+15, the answer is 3/10

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

the value of x is equal to 0.