I'm doing a extra credit worksheet for math it says “Graph the following equation (Don’t forget to get y alone first, then use the slope and y-intercept to graph” the equation I’m doing right now is y= 1/2x + 18 can somebody please help me

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  see below for a graph

Step-by-step explanation:

Your equation has "y alone". It is written in "slope-intercept form."

  y = mx + b . . . . . . . where m is the slope and b is the y-intercept.

Comparing your given equation ...

  y = 1/2x + 18

to the above form you see that m = 1/2 (the slope) and b = 18 (the y-intercept).

The y-intercept is where the graph crosses the y-axis, so the first point you can plot on the graph is at (0, 18) on the y-axis.

The slope of 1/2 tells you the ratio of "rise" to "run" is 1/2. That is, the "run" (change in x) is 2 units for each "rise" (change in y) of 1 units

  m = rise/run = 1/2

So, another point (or several) can be found by moving twice as many units to the right as you move up. For example, if you choose 10 units right, to x=10, the point will be 10/2 = 5 units up from y=18, at y = 23. That is (10, 23) is another point on the graph.

Now, you have points (0, 18) and (10, 23) on the line. The graph will be a straight line through those points.